Hey guys, I know you don’t believe the AE were capable of comprehending pi, let alone their ability to comprehend, demonstrate and make use of the Kepler conjecture (densities of cubic and hexagonal packing of spheres) in the construction of G1, now that would really be a stretch wouldn’t it?

But you see the AE did not build (a mountain) the pyramids to encode pi or any other mathematical concept, they, like we, used the concepts to explain universal phenomena! The length of the cubit being 1/20th the surface area of a 36 inch sphere is derived and demonstrated by the Kepler Conjecture pi / (3 Sqrt 2). It is therefore possible to calculate the cubit from the Kepler Conjecture! Calculate the following: pi / (3 sqrt 2) = 0.740480489…. 0.740480489 / (14/11) = .0581806099 the inverse being 1.718785694… 1.718785694 * 12 = 20.62542833 inches which is a acceptable value for the cubit according to Petrie. The Kepler conjecture has the same relation to the Royal Egyptian cubit as the area of a circle has to the area of a square whose circumference and perimeters are equal as demonstrated by G1, 14/11.

Having shown in an earlier post the circular and spherical characteristics demonstrated by G1, Red and Bent pyramids [www.hallofmaat.com] and demonstrating the cubit by concept is: (14/11) (99/70/(22/7/3)) = 189/110 feet, 1.718181818 feet...equal to 1/20th the surface area of a 3-foot circumference sphere. It is all but impossible to accurately translate this into today's mathematical terms. The closest translation to our concepts would be (sqrt(1.618033989) sqrt(2))/(pi/3) which yields a value of 1.717830068...feet, which multiplied by 12 inches = 20.61960816 inches, still within Petrie's limits, but misses the intended meaning.

The above are irrational numbers and we know the Ancient Egyptians did not use irrational numbers. I can spell it out in unit fractions if you wish, but I doubt anyone would be able to wade through calculations in that form and actually comprehend what was written. So expressed in proper and improper fractions the figures as the AE would have calculated in rational form: (22/7) / (3 * 99/70) = (20/27)…0.740740740…(20/27) / (14/11) = 110/189 = the inverse of the Royal Egyptian Cubit which is 189/110…189/110 * 12 = 20 34/55 inches, that is (20.6181818…inches).

In rational numbers the Kepler conjecture times the Royal Egyptian cubit equals the rise-run of G1. (14/11) i.e. (20/27 * 189/110 = 14/11)
So is the Kepler conjecture just another artifact of G1?

The Kepler’s formula for cubic and hexagonal sphere packing (22/7) / (3 * 99/70) divided by (14/11) = 110/189 inverse Royal Egyptian Cubit when combined with J. Michell’s ancient formula for calculating earth dimensions will provide an accurate figure for the polar radius of Earth. 110/189 * 12^7 = 20854491 3/7 feet divided by 5280 is 3949 5/7 miles.

(110/189 * 12 = 6 62/63) (6 62/63 * 12 = 83 17/21) (83 17/21 * 12 = 1005 5/7) (1005 5/7 * 12 = 12068 4/7) (12068 4/7 * 12 = 114822 6/7) (114822 6/7 * 12 = 1737874 2/7) (1737874 2/7 * 12 = 20854491 3/7 feet) = (110/189 * 12 ^ 7 = 20854491 3/7 feet) = Earth’s Polar Radius in feet. Not too bad for a bunch of dumb guy's who lived 4500 years ago and didn't comprehend the concept of pi.

Expressed in today’s math concepts (pi/(3 sqrt(2)))/sqrt(1.618033989) 12^7/5280 = Earth polar radius = 3950.523043 miles. In other words the Kepler conjecture times the square root of phi times J. Michell’s ancient formula for calculating earth dimensions divided by the number of feet in a mile equals the Earth’s polar radius within a mile or two.

I know you won’t believe the AE were capable of comprehending any of the above, so their being able to comprehend and employ zero point energy....