Hi Jacob


Sirfiroth Wrote:
-------------------------------------------------------
>
> Are you aware that you started with a value of pi
> (37 5/7 / 12 = 22/7). Actually 28/33 is (14/11 *
> 2/3) the values of sphere (28) to cube (33)
> surface areas.
>

Well yes I did because I reverse engineered the value 28/33 were I had the diameter of 12 and circumference of 37 5/7. And yes I used 22/7 to find the circumference.


> Surface area of sphere side^2 * 14/11 * 4 = area
> times 4 = surface area of sphere, translating
> surface area of the sphere to surface area of the
> cube 14/11 * 2/3 = 28/33 sphere surface area
> divided by 28/33 equals surface area of a cube in
> the same ratio as the seked circle and square.
> Volume of sphere Area = side^2 * 14/11 * 4/3r =
> volume 4/3r * area
> for translating volumes of spheres to cubes
> (14/11^2 * 2/3)
>

Oops! Sorry about that I remember reading you posting but for some reason glossed over the part about 28/33. It may have been because it started with (Surface area of sphere) and it was a long posting. I assure you I was not trying to take credit for 28/33 at your expense. To be honest I was trying to look at it from the AE point of view from their solution to finding area of a circle. Thank you for the 14/11 * 2/3 = 28/33.


>
> The ratios of G1 indicates the circumference of
> the circle and perimeter of the square are equal,
> 1760 cubits, G1 states the radius of the circle,
> or height of the pyramid, divided by 7 times 11
> equals the base of the pyramid or the side of the
> square giving the following ratios:
> Radius 7 units to side 11 units 7/11
> side 11 units to diameter 14 units 11/14 (run-rise
> of the 5 1/2 seked)
> side 11 units to perimeter 44 units (4 * 11 = 44)
> since the circumference is equal to the perimeter
> and the circumference is 44 units.
> radius is 7 therefore the circumference to radius
> ratio is 44/7
> the circumference to diameter ratio is 44/14 or
> 22/7
>

It’s all-good! I’m very aware of all this I have worked through it many times seked 5 ½ works extremely well.



> Evidently you noticed in the RMP and MMP the
> Ancient Egyptians worked primarily with areas and
> volumes and did not demonstrate any of our current
> concepts regarding pi. They did demonstrate that a
> unit squared divided by a fractional value will
> get the area of a circle.
> G1 demonstrates that the diameter squared / 14/11
> = area of circle or side squared * 14/11 = area of
> circle.
>
> Regards,
> Jacob
>


Sometimes I’m a bit slow when it comes to catching on to a subject but hopefully I’m getting there. I’m seeing that they could have taken (C * (28/33) / 8 * 3) to find a diameter or (C / 3 1/7 = D) or (seked 5 ½) and lobo-hotei’s C= 2(D+1/9) * 10/7(or 99/70) good stuff 4 different ways and most interesting as far as I’m concerned.

Regards,
RLH