affiliator Wrote:
-------------------------------------------------------
> Sirfiroth Wrote:
> --------------------------------------------------
> -----
> > Hi Nick,
> >
> > If you wish to prove pi as the ratio used by
> the
> > Ancient Egyptians you are free to do so
>
> Hi Jacob
>
> Woah, stop right there. I am not seeking to prove
> anything, merely document what I feel the builders
> may have intended. Might I be wrong? Of course.
> Can you admit to the same?

I sure can, but based on what I have found someone will have to prove me wrong with solid evidence.

> > I
> > have stated many times the Ancient Egyptians
> were
> > aware of pi, even in its irrational form,
> but
> > chose not to use it. I didn't expect you to
> > understand, but if you will really look at
> the
> > concept of the seked you might well see the
> sphere
> > as space and the cube as time and the seked
> as a
> > common formula to measure both with one
> unit.
>
> Why are you using it then? 1296000/4 x 11 x 7 is
> 1296000/(44/7) whatever way you look at it. You
> can't seriously be trying to argue otherwise here!

Why not, the 5 1/2 seked has a component pi is missing, that being the component of time. in the space-time continuum that relates to the sphere-cube geometry.

> Pi is the key to circular and spherical geometry,
> not seked.

Maybe in your world Nick, You evidently miss the spherical and cubic demonstration with the seked. <[www.hallofmaat.com];
Spherical Geometry with the seked.

Area = (side^2 * 14/11) or (side^2 / 11/14) (third option) diameter^ / 14/11

Surface area of sphere side^2 * 14/11 * 4 = area times 4 = surface area of sphere, translating surface area of the sphere to surface area of the cube 14/11 * 2/3 = 28/33 sphere surface area divided by 28/33 equals surface area of a cube in the same ratio as the seked circle and square.
Volume of sphere Area = side^2 * 14/11 * 4/3r = volume 4/3r * area
for translating volumes of spheres to cubes (14/11^2 * 2/3)

> Try using an alternative seked than G1
> that doesn't incorporate an approximation of pi
> and see how you get on.

Depends on the purpose, 20:21:29 Triangle 6 2/3 seked of Red Pyramid, the 3-4-5-6 triangle of the 5 1/4 seked of Kahfre or the 5 3/5 seked of Menkaure or the 4 9/10 seked of Bent pyramid lower and the 7 7/20 seked of the upper portion? Each one has a story to tell and it does necessarily revolve around pi.

> The fact is seked needs to
> incorporate pi to hold any significance to
> circle/sphere geoemtry, but pi does not need to
> incorporate seked - thats an obvious fact.

I think you might be missing the point regarding how the Ancient Egyptians employed seked. any circular calculation will use the 5 1/2 seked, any calculation requiring 3-4-5-6 triangle will use the 5 1/4 seked, they are examples which denote the concepts, principles and elements of their system of mathematics, although the inter-connectivity of the various seked might surprise you, it certainly surprised me. G3 or Menkaure pyramids has a seked of 5 3/5 that is 5+1/2+1/10 = 5 units rise vertical to a run of 4 units horizontal, that is a triangle without a hypotenuse, just as the 5 1/2 seked is a 14/11 rise run, a triangle without the hypotenuse, think of them as major and minor axes as in the cartesian coordinate system, Keplerian elements as only one of the seked functions among others. Which I have found much less complicated than our system of angles and preform the same function.
Just how much have you actually worked with the seked and unit fractions that enable you to make the determination: pi does not need to incorporate seked - thats an obvious fact.

> In any case, all the recent heavyweights in ancient
> metrology such as the late John Michell, John Neal
> who collaborated with Michell to help define the
> ancient system, and of course Petrie himself
> readily acknowledged that the AE employed pi.
> Indeed Michell's 24883.2 meridonal Earth value
> hinges on pi - 44/7 for mean radius and 6.3 for
> polar radius - both highly accurate to modern
> values.

John Michell on page 138 of New View over Atlantis gives the following values
1. 44 * 12^6 as the Earth Mean circumference, that is 131383296 feet, 131383296 / 5280 = 24883.2 miles.

2. 7 * 12^6 as Earth Mean Radius, that is 20901888 feet, 20901888 / 5280 = 3958.690909...miles The same figure for the radius is calculated by the AE using the perimeter of G1 squared divided by the Eye of Horace (63) 9! that is (1x2x3x4x5x6x7x8x9^2/10)/63 = 20901888 = 7 * 12^6

> So far you haven't shown me anything with
> seked that simple pi ratios in conjunction with
> Neal and Michell's system of metrology don't do
> better.

Never read Neals work, but I did build on Michell's work which I found to be very basic and somewhat confusing, but you can add my contribution of using the inverse of the Royal Egyptian cubit of 189/110 feet, 110/189 * 12^7 = Earth Polar radius, 20854491 3/7 feet 20854491 3/7 /5280 = 3949 6/7 miles. 131383296/63 = 20854491 3/7

Earth Polar Radius as calculated by Michell, Newton and others, 20854491 3/7 / 12 = 17378742.8571428…* 756 = 1313832960 756 = (63*12)the cubit of the Ancient Egyptian geodetic grid their method of dividing the earth surface. The one that states G1 sits exactly 131383296 inches from the equator (12^3 / 10) miles 30º. Longer Egyptian cubit is 110/189 * 12^6 = 17378742.8571428 that is 1/12 Earth polar radius

Longer Egyptian cubit is: (38016/21875) feet. or (456192/21875) inches

12,000,000 units = Earth's Polar Radius
75,600,000 units = Earth's Mean Circumference

For those who don't know, according to Wikipedia The Bohr radius is a physical constant, approximately equal to the most probable distance between the proton and electron in a hydrogen atom in its ground state. Bohr radius our calculated we estimate it at 52.9177211*10^-11 m or 53 picometers is 1.73614571*10^-10 in feet.

38016/21875
1.737874285*10^-10 feet = Bohr radius as the Ancient Cultures calculated it.

There are other similarities too many to be coincidence from the other ancient structures.
How does the Longer Egyptian Cubit related to match other ancient structures?

28 units = Inner radius of Stonehenge Sarsen Circle 48 2064/3125 feet
30 units = Outer radius of Stonehenge Sarsen Circle 52 596/4375feet
42 units = Harelston's estimate for the Height of Pyramid of Quetzalcoatl 72 3096/3125 feet
56 units = Inner Diameter of Sarsen Circle 97 1003/3125 feet
58 1/3 units = One Geographic Second 101 47/125 feet 101 47/125*1296000=131383296 EMC
60 units = Outer Diameter of Sarsen Circle 104 1192/4375 feet
84 units = Harelston's estimate for the Height of Moon Pyramid 145 3067/3125 feet
120 units = Base of Pyramid of Quetzalcoatl 912384/4375 = 208 2384/4375 feet
126 units = Harelston's estimate for the Height of Sun Pyramid 218 3038/3125 feet
168 units = Diameter Aubrey Holes (Stonehenge) 912384/3125 = 291 3009/3125 feet
176 units = Inner Circumference of Sarsen Circle 305 18941/21875
256 units = Short side of Moon Pyramid Base 444 19596/21875
288 units = Long side of Moon Pyramid Base 500 11108/21875
406 ¼ units = Side Base Pyramid of Khafre 706 2/175 feet
432 units = Side Base of Sun Pyramid 750 16662/21875 feet
435 units = Side Base Great Pyramid 755 4267/4375 feet

437 1/2 units = South side Socket Base Great Pyramid 760 8/25 feet (1.728 * 440 = 760 8/25)gives the ratio of 175/176 Michell found. Just as the base of G1 has 440 cubits of 20 34/55 = 756, 756/441 = 12/7 or 20 4/7 inches the cubit of the Queens chamber, which is 20.5714285714 inches this provides the ratio of 441/440 between Earth Mean and Polar radius that Michell found. (the south side socket base Petrie measured 9123.9 inches 760.32 * 12 = 9123.84 inches) <[www.ronaldbirdsall.com]; multiplied by 4 equals 1/10 1º by their geographic grid system.

480 units = Perimeter of Pyramid of Quetzalcoatl 834 786/4375 feet
528 units = Outer Circumference Aubrey Holes (Stonehenge) 917 13073/21875 feet
756 units = Side Length of Citadel at Teotihuacan 1313 2603/3125 feet
1088 units = Perimeter of Moon Pyramid Base 1890 17658/21875 feet
1440 units = Distance Between Moon and Sun Pyramid 2502 2358/4375 feet
1625 units = Perimeter of Pyramid of Khafre 2824 8/175 feet
1728 units = Perimeter of Sun Pyramid Base 3003 1023/21875 feet
1740 units = Perimeter Core Base Great Pyramid 3023 3943/4375
1750 units = Perimeter of Socket Base Great Pyramid 3041 7/25
3024 units = Perimeter of Citadel 5255 1037/3125
3500 units = One mean minute of Latitude 6082 14/25 (twice the socket base perimeter G1)
4536 units = Length of The Way of the Dead (Teotihuacan)7882 3118/3125 feet
210,000 units = One mean Degree 364953 3/5 feet. 364953 3/5 * 360 = 131383296 feet EMC
12,000,000 units = Earth's Polar Radius 2085449 1/7 feet
75,600,000 units = Earth's Mean Circumference 131383296 feet

> But if it works for you then fill yer
> boots as they say!
>
> Regards
> Nick

All of the above is derived through the uses of the 5 1/2 seked, pi not included.
This is just the tip of the iceberg. All of this information came from the Kings Chamber. Where most see and empty room is a host of information in the layout and architectural details and the room is read from the top down just as the seked is the cotangent of the gradient displayed by G1.

Regards
Jacob