Hi Wayne ...

Forgive me but I wish to dispute your theory.

Presented below is your diagram.



Let's start with your inner circle which is, you say at the 3/4 mark. That would make it 3/4 of 440 or 330 cubits. YOu state that the vertical downward meassurment is 250 cubits. Calling upon Pyrthagorus we get:

330 squared = 250 squared + 'X' squared
X squared = 330 squared - 250 squared
X squared = 108900 - 62500
X squared = 46400
X = 215.41


'X' squared = 440 squared + 220 squared
'X' squared = 193600 + 48400
'X' sqaured = 242000
'X' = 491.94 = 491 + 11 1/4


Our next triangle using centre of P2 is

491.94 squared = 250 squared + 'X' squared
'X' squared = 491.94 squared - 250 squared
'X' squared = 242000 - 62500
'X' squared = 179500
'X' = 423.67

Therefore 423.37 - 215.41 should equal 1/2 of baselength of P2

423.37 - 215.41 = 208.26 (This should be 1/2 base of P2)

So 2 x 208.26 should equal bse length of P2
2 x 208.26 = 416.53 ... This is NOT the length of the top face of P2. The top measurement is 411.04.

Therefore I feel that since geometry never lies that your 1/4 theory does not fit.

sorry
Best
Don Barone

" If everything is simply a coincidence what then is the point of studying or measuring or analyzing anything in the ancient world ?" db