In my monograph on the Grand Gallery I have shown that the architect devised a scheme to square the circle simply by measuring, so that irregular numbers are automatically rounded to the nearest whole number from measurement ie no need for calculation.
Let me try to explain further.
Construct a right angled triangle with a slope length = sr280, base = 15, height = sr55, all in royal cubits.
(The sr55 is the vertical side of a triangle with a slope length of 8 and a base of 3)
The vertical height of the Grand Gallery is sr280 royal cubits near the north end wall.
The perpendicular height of the Grand Gallery is 15 royal cubits near the north end wall.
Flip over the triangle and you get the symbolic slope of the floor.
(The measured slope of the floor is close to the theoretical angle 26 degrees 18.5 minutes).
How do we square the circle from this slope?
Simply project 4 times the radius of any circle on to the sloping floor of the Grand Gallery, and then measure the vertical displacement.
For example, a circle with a radius of 10 royal cubits.
A length of 40 royal cubits marked off on the slope corresponds to a vertical rise of:
the side-length of the equal area square
In theory it is approximately 365 x 34/25 digits, and 364.99.. x 34/25 digits on my calculator, where 34/25 digits is a symbolic unit of length.
The proposed triangle corresponds to the pi value 22/7 exactly.
sr55/sr280 x 40 = 17.728.. royal cubits
sr(22/7 x 10 x 10) = 17.728.. royal cubits
I know you are unhappy with the division of the digit into 25 parts. Cubit rod evidence shows that AE divided the digit into 2 divisions, 3 divisions and so on up to 16 divisions, as you kindly pointed out. The division is simply n + 1, where n increases from 1 to 2 to 3 to 4 etc. There is no reason to stop at n = 15 in an arithmetic scheme for a symbolic unit of length.
There was no need for the division to have existed, but the lean-in of the East and West Walls of the Queen's Chamber corresponds to precisely 34/25 digits where the displacement of the Niche from the peak of the chamber equates to 34 digits.
The length of 34/25 digits was symbolic 1 day.
The mini square of 365 x 34/25 digits is the equal area square of the King's Chamber Circle. Multiply by 25 as the cubic diagonal of the King's Chamber and you get 365 x 34 digits.
This equates to 25 x 365 x 34/25 digits or 9125 x 34/25 digits, where 9125 is the number of days in 309 lunar months. This is the east side-length of the Corner Sockets.
The full square has a theoretical perimeter of 1,460 x 34 digits.
Follow the logic through, and consider the internal architecture. Then you should find that G1 expressed the number of lunar months in 1,461 calendar years, which I have interpreted as 1,460 solar years.
Mark
Edited 1 time(s). Last edit at 10/19/2011 01:29PM by Mark Heaton.