Hi Mark,
Return for a minute to your statement:
We know that 9125 days is the number of days in 25 calendar years, so we end up with a length of 34/25 digits symbolic of 1 day, and 1,460 x 34 digits symbolic of 100 calendar years of 365 days..
I don’t think so, 1460 x 34 = 49640…49640 / 365 = 136 calendar years, it is 1460 x 25 = 36500 = 100 calendar years
Then you also said:
If the royal cubit was 20.60 inches then 34/25 digits was 1.0006 inches to 4 decimal places
Not really, but calculating without defining the length of the, but using digits with no mathematical value other than 1 cubit = 28 digits. The results will give the true margin of error in the calculations regardless of the length applied.
Scale: one digit = one digit:
(34/(25 x) = 28) (x = 17/350) = 0.0485714285714…true error, not the 1.0006 posted.
Mark Heaton wrote:
My hypothesis is 365 x 34 digits for the east side-length of Corner Sockets
(34/(25 x) x 365 x1461 = 49640) = (3626202/(5 x) = 49640) therefore (x = 1461/100)
34/(25 (14+1/2+1/10+1/100)) x365 x1461 = 49640
multiplying 25 x (x = 1461/10) = 365 1/4
34/365/1/4 x 365 days x 1461 years = 49640…49640 / 4 = 12410 digits
Now for the side length in digits with no mathematical value other than 1: your figure of 12410 as calculated in relation to the Sothic cycle above by the equation, 12410 divided by the number of digits in a cubit that being 28 will provide the number of cubits, not length.
12410 / 28 = 31024/70 = 443 3/14 cubits
Then: (443+3/14)^2 = r^2 * (22/7) which is saying 196438 177/196 = (22 r^2)/7 therefore r = 6205/(2 sqrt(154)) or r = 250.006574588874237594177812771311677654565095180094110420...which is an irrational number and does not fit within the unit fractions system of the Ancient Egyptians, therefore: the radius of the circle is not 250 cubits and one cubit is not equal to one day.
Regards