Hi Clive,

Using Greek Mathematical concepts to understand Ancient Egyptian structures that were completed before the Greeks thought of the concepts being used, from where I stand it can't be done.

Clive wrote: What I think you are trying to say is...
A circle enclosed by a square of perimeter 4 will have a circumference of 22/7...AKA pi...that's factual.

Sorry Clive, it may be factual, but that is not what I am trying to say, what I am saying is: a circle with a circumference of 22/7 is interlace with a square with a perimeter of 22/7, with the areas of circle and square being a 14/11 ratio respectively. The AE way! it is very simple to divide a circumference by four, four (22/7 * 14/11) makes all of the correct calculations for you as shown here in unit fractions:

7 * 7 = 49 area of square
49 * 14/11 = (62 + 1/4 + 1/11 + 1/44) (62 4/11) area of circle
(62 + 1/4 + 1/11 + 1/44) / 14 = (4 + 1/3 + 1/11 + 1/33) radius of circle
(4 + 1/3 + 1/11 + 1/33) / 28 = (1/7 + 1/110 + 1/140) (7/44) (1/28 radius)
(1/7 + 1/110 + 1/140) * 176 = 28

It is amazing to think three circles with a radius of 10-cubits will construct walls, ceiling and floors of the king’s chamber. Then we find the KC length times 14 equals 5773 1/11 the height of G1, 22 times KC length equals G1 base dimension. 7 times the KC length is the base of the Sphinx. And of course 11 times KC length equals one-half base G1. I believe that includes all of the values that make up the number 4. (22/7 * 14/11)

Clive wrote: The "only" numerical value where a circle's diameter equals its area is 4/pi.

D = 4/pi....A = 4/pi

The circumference of any circle is inherently pi/4, just as the square root of 2 is inherent in the diagonal of any square.

Clive wrote: That's what the builders wanted us to realize...the more complex geometric circle/square/linear/area association. And it is successfully illustrated using a single triangle built on a (7x4)/22 ratio...or...[14/11]...or 4/pi. Then they confirmed using the base angle of G2.

I have found the along with what you stated the AE were very adept at three dimensional shapes such as spheres, cubes, cones frustums and hyperbolic shapes.

Each of the pyramids seked are arrived at by specific mathematical process as shown below:
8/9 / 44/63 = 14/11 G1...51d 50m 33.98s (44/63 = 2pi/9)
G1 14/11 / 21 * 22 = 4/3 G2...53d 7m 48.37s (22/21 = pi/3 hyperbolic)
G2 4/3 / 140/99 = 33/35 Red...43d 18m 55.14s (140/99 rational square root 2)
Red 33/35 / 2/3 = 99/70 lower Bent...54d 44m 13.16s John Legon (rational square root 2)
Bent lower 99/70 * 2/3 = 33/35 upper bent...43d 18m 55.14s
G1 14/11 / 56/55 = 5/4 G3...51d 20m 24.69s

Regards,
Jacob