If we apply the 28 divisions of the cubit to G1's side lengths we find a curious result (noting that treating the side length as a whole of parts;

9069.4825 inches = 439.8391125 royal cubits (@ 20.62 inches per cubit)

As noted by Petrie the hieght of the pyramid is divided into "5" parts of 56 cubits each, thus rendering 280 royal cubits, such that divided by 28 we have ten parts of 10 royal cubits each, kind of simple there.

439.8391125 (439 + 1/2 + 1/3 + 1/174) divided by 28 = 15.70853973 (15 + 1/2 + 1/5 + 1/118)

15.70853973 divided by "5" = 3.141707946! (3 + 1/8 + 1/60)

Interesting notion; The base area of G1 equals 140^2 x 3.141707946^2 (pi^2)

thus; 439.8391125^2 = 140^2 x pi^2

Is this one way of squaring a circle??

Best Regards,

B.A. Hokom