Hi Hermione.

Forgive me but I am still working on the problem. I happened to be trying to start saving all my 9435 images at Image-shack in case it ever went under and I came across this image of mine which I had forgotten. It shows that that the floor of The King's Chamber MAY BE in a Phi relationship with the enclosed circle. Here is the image:



Here is a previous image of my work on the circle where I had it calculated to 213.90 cubits



However if we accept that the floor of the King's Chamber is in a Phi relationship to the circle then we get 82.09 (floor in cubits above base) and times Phi or 1.618034 = 132.8244 cubits to the top of the circle making the circles diameter 92.09 + 132.82 = 214.91 almost exactly 1 cubit difference. Interesting. I am still looking for a formula to figure out the radius of the circle that I can understand. Basically we have King's chamber floor x Phi squared or 2.618034 = 214.91

Here is the final image:



If anybody can figure this out I would be indebted. I am using base of G1 @ 439.823 cubits, height of G2 @ 280 cubits and slopes at 356.035 cubits

regards
db

"There is nothing as impenetrable as a closed mind"
and ..." if everything is a coincidence what is the point of studying or measuring or analyzing anything ?" db