Hi Robin I started reading your paper but had trouble getting by the first couple of pages. Firstly given the mind set of The Ancient Egyptians and their mathematics It would have been impossible for them to have designed anything using the square root of 2 or square root of 3 for that matter. I have just recently been in discussions with John Legon and have challenged him on his plan of Giza. Mainly since square root of 2 (x 1000) is 1414.21356 and the measurement at Giza is 1417.43 I called into question his reasoning that although the builders were within inches north and south on the shorter distance they were out almost 3 cubits. It makes no sense The ratio of The Giza Plateau is a 9 by 11 rectangle NOT square root of 2 by square root of 3. Also and this is very important you have the 1100 mark south of the north face of G1 at the base of G2. This is not what is in the field. It is a bit over 1101 and not 1100.00. Even John admits to that and that is why he made the top of The Bent 110.1 cubits but that is another discussion. The Ancient Egyptians knew no irrational numbers they couldn't because they only used fractions. It is impossible to show square root of 2 or square root of 3 as a fraction thus it could not be as you and John Legon wish it to be. Given the fact that both of your opening set ups are, in my humble and learned opinion in error it was pointless to continue reading.

Perhaps this might help you understand where I, a former staunch defender of Pi and Phi throughout the ages, is coming from. I finally realized that The Ancient Egyptians operated on something I had never ever heard mentioned before. They operated on a base 7 unit system. We have our base 10 and decimal system and the Sumerians (Babylonians) had their base 6 or 60 system. So what that means is that ALL of these figures can be obtained using multiples of 7. Let us do square root of 3 first. 10,000,000 / 280 (40 x 7) gives us 35,714.28 or 35,714 and 2/7th inches (actual according to Petrie is 35,713.5). Using the standard of 20.62 inches per cubit we get 1732.0216156297630594429818484135. Now surprisingly if we take the reciprocal of this we get 0.00057736 and if we multiply back by 10,000,00 we get the height of The Great Pyramid at 5773.6 inches. I had long been convinced it was 5773.5 or square root of 3 / 3 x 10,000 and now when we divide 5773.6 inches by 280 we get a nice clean 20.62 inches in a cubit. And most importantly all of my figures can be expressed in fractions.

Equally compelling we have 99000 (99 x 1000) / 7 to get 1414.2857142857142857142857142857 or 1414 and 2/7ths (and within 99.999 % of the correct value). So since it was so easy to calculate and they are out 3 cubits something else was meant. Let us go with Jim Allison who I believe first proposed a 9 by 11 grid. If we let 1732.0216 (can't figure out the fraction here, sorry) and divide by 11 we get 157.4565 ... x 9 = 1417.1086 almost precisely what is found at Giza. So as I tried to explain to John and I am suggesting to you The Giza Rectangle is not square root of 2 by square root of 3 but is in fact in the ratio of 9 to 11.

Regards
Don Barone





"There is nothing as impenetrable as a closed mind"
and ..." if everything is a coincidence what is the point of studying or measuring or analyzing anything ?" db



Edited 1 time(s). Last edit at 08/19/2015 03:43PM by Ahatmose.