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May 3, 2024, 4:58 am UTC    
February 28, 2012 02:19PM
Let us suppose that the intended height of the Niche to the footing of the floor was the height of G1 divided by 10 pi where pi is 22/7.

The intended height of the Niche N1 was 249 1/2 digits on this basis.

Now stand and face the East Wall. It leans in at 14 arc minutes according to Petrie. This is the cotangent of 246.

Let us suppose that the missing floor had a depth of 3 1/2 digits.

What do we now see? The height of the Niche N2 is reduced to 246 digits, the same as the cotangent of the lean-in.

The intended lean-in of the East Wall now appears as 1 digit from floor level to the top of the Niche.

Now look left to the Entrance Doorway. The height D1 is 91 1/2 digits to the footing of the floor, but the height D2 to the proposed floor level is now 88 digits, which is pi royal cubits.

Now look up to the East Wall Peak. The height E1 to the footing of the floor is 334 1/2 digits, but the height E2 to the proposed floor level is 331 digits

E2 is the width of the chamber (280 digits) divided by the length of the chamber (309 digits) multiplied by 365 1/4 digits.

Now take the height of the East Wall Peak E1 at 334 1/2 digits and divide by the height of the Niche N2 at 246 digits. The lean-in from the footing of the floor to the East Wall Peak is this fraction multiplied by 1 digit, which happens to be 1.00 inches.

Mark






Subject Author Posted

pi in QC of G1

Mark Heaton February 28, 2012 02:19PM

Egyptian Pi

Hermione February 28, 2012 03:42PM

Re: Egyptian Pi

Mark Heaton February 28, 2012 04:56PM

Re: Egyptian Pi

L Cooper February 29, 2012 08:05AM

Re: Egyptian Pi

Mark Heaton February 29, 2012 12:32PM



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