Hi all.

This is a simple and logical solution to the angles at The Bent Pyramid. It was when Petrie mentioned in his notes that a slope distance of 7 with a base 5 produced the angle he found that I decided to put this together. Most ingenious if I do say so myself.

First start with a rectangle 7 by 10



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Draw an oval simply because I love ovals. No not really this is the same oval we have seen before and the one I suggest produces the arc on The Sakkara Ostracon.



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Draw two diagonals to the half way point



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Turn diagram on it's side to produce a pyramid.



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Doing the math we find the the angle is 54° 27' 44.36"

Following Petrie's advice draw a line with the slope distance 7 units.

This yield the angle 44° 24' 55.11"



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Measuring 6 units up draw a line parallel to the slope on the right hand side of the red pyramid.



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Draw a pyramid (in purple) with the height distance 6 and slope parallel with the original red pyramid. draw a bent pyramid form using as the transition point where the purple and the blue pyramid meet.



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Colour in for dramatic effect.

The Bent Pyramid solved.



This time everything seems to check.

Don Barone

"There is nothing as impenetrable as a closed mind"
and ..." if everything is a coincidence what is the point of studying or measuring or analyzing anything ?" db