To all intents and purposes the perpendicular height of the Descending Passage (and the Ascending Passage) is 2.286rc/47.16"

Why 2.286rc?
Simple, like the width at 2rc it's from the King's Chamber doorway.

KC doorway width = either 1/10 of the Chamber's length @ 20rc = 2rc, or 1/5 of the Chamber's width @ 10rc = 2rc.
The height of the doorway is simply 1/5 of the height of the Chambers walls @ 11.429rc = 2.286rc.
But why 11.429rc for the height of the Chamber's walls?
Again its very simple, it's so that the perimeter of the Chamber's side (north and south)walls = the length of the wall @ 20rc multiplied by 22/7.

As for the starting point - i.e. the Chamber's width and length @ respectively 10rc and 20rc, is there anything much more basic than a 1x2 rectangle or two squares placed next to each other?

The one-in-2 (26.56 degs) gradient is nothing more than what you get by drawing a diagonal across the floor of the King's Chamber.

Why there should be any need to make things more complicated or complex than this is beyond me.

MJ

We can't all be right, but we could all be wrong ...



Edited 1 time(s). Last edit at 11/25/2009 12:45PM by MJ Thomas 2.