In another of this gentleman's video he is still claiming Hemiunu's tomb is 100 royal cubits and thus The Hemiunu Template is a square 200 by 200 royal cubits. He further claims that the air shafts exit at this point.

So let's do some simple math ....

if 1/2 base is 100 and we use 7 / 5.5 as the ratio of The Great Pyramid then the height is simply 7/5.5 x 100 or 127.27273 cubits and since we can almost all agree that the height of The Great Pyramid is 280 Royal Cubits then according to him the shaft exits at 280 - 127.27273 or at the 152.727273 cubit mark which if we use 20.62 which is think is correct since the top of the 64th course is precisely 2062.0 inches we get a value of 152.727273 x 20.62 and we get 3149.24 inches and as you can see in this image: [donbarone.altervista.org] Petrie has as the bottom of the 104th course or equally correct is saying the top of the 103rd course.

Now a lot of us have used 99 as 1/2 base and we find it much more eloquent in it's overall design and we get 154 and 126

Proof: if 1/2 base is 99 and we use 127.27273 we get precisely/exactly 126 Royal cubits thus the exit point is at 154 cubits and times 20.62 gives us in inches 3175.48 and according to Petrie IS THE TOP OF THE 104TH COURSE !

So as this gentleman observed that this one course change gives us precisely 2 cubits (or 1 if we use 1/2). I wanted to find out why and sure enough this happens because course 104 is, and has to be, equal to 7/5.5 x 20.62 or 26.244 inches and Petrie has measured the 104th course as 26.3 inches and I have to say is an almost certain proof that the angle was indeed supposed to be and designed as 7 / 5.5 or 440 by 280 Royal cubits

Images showing this:

[donbarone.altervista.org]

[donbarone.altervista.org]

db

"There is nothing as impenetrable as a closed mind"
and ..." if everything is a coincidence what is the point of studying or measuring or analyzing anything ?" db