Don Barone Wrote:
-------------------------------------------------------
> Hi Hermione ...
>
> In the post he linked to this is what is found.
>
Quote:
> Hi Clive ...
>
> Forgive me it is yours.
>
> I just blew it up and changed your E to W and
> changed your 1412 to 1412 + 1/4
>
> I have used your measurements of 807 cubits but
> modified it to read 605 + 1/4 as opposed to 605
> even. It all flowed once I saw that all numbers
> were starting to fit perfectly with known
> fractions.
>
> For example 1412 + 1/4 / 7 = 201 + 3/4
>
> 201 + 3/4s x 4 = 807 exactly ... while
>
> 201 + 3/4s x 3 = 605 + 1/4 ... while
>
> 201 + 3/4s x 5 = 1008 + 3/4s which is the distance
> of a right angled triangle with sides 807 and 601
> + 1/4
>
> Isn't it wonderful !
>
> Do you like it ?
>there are two values listed on this post
> ... 605.25 and 601.25 and lobo couldn't even
> figure out which one was correct and I expect him
> to understand the rest.
Don, I simply don't understand. If I can go over it again:
You say: 201 + 3/4s x 5 = 1008 + 3/4s which is the distance
> of a right angled triangle with sides 807 and 601
> + 1/4
Setting aside the rest of your arguments, you're saying here that 1008.75 is the
hypotenuse (if by "distance" you meant "hypotenuse"?) of a right-angled triangle whose other two sides measure 807 and 601.25?? But, if I perform that calculation, I get exactly the same answer as Lobo, i.e., 1006.35 ... Where have I gone wrong?
Hermione
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