Don Barone Wrote:
-------------------------------------------------------
>
> But now a new proposal for what is meant by the
> crescent Moon and Sun disc.
>
> It is now my conviction that what the crescent
> moon is signifying is ONE DAY OF THE MOON'S CYCLE
> !
>
> and now combining that and the actual diameter of
> The Moon we get this:
>
> Mean radius: 1,737.10 km (0.273 Earths)
> Equatorial radius: 1,738.14 km (0.273 Earths)
> Polar radius: 1,735.97 km (0.273 Earths)
> Sidereal rotation period: 27.321582 d
> (synchronous)
>
> So one day could equal 1,735.97 x 2 / 27.321582 =
> 127.077
>
> And I now propose for G3 a height of 127.07 cubits
> (among other things it may represent).
>
> I will explain the sun disc in my next post.
>
> humbly
> Don Barone
>


Before you move on to the sun could you explain more on this moon subject?

By this “ONE DAY OF THE MOON'S CYCLE” are you saying that from crescent Moon to the same crescent Moon is one day? If so by this I would think you mean one Moon day not your “27.321582” Earth days it takes for a sidereal month?

I’m not getting the relationship between the Moons diameter and the number of earth day in a sidereal month. So if you are dividing the Moons diameter by the number of Earth days in a sidereal month then what is the 127.077 equal to (km per day)? So is that suppose to mean that one earth day is equal to 127.077 km?

Its my understanding the Moon makes one revolution on its axis for every complete cycle around the Earth therefore we always see the same side of the Moon (tidal friction).

Regards
RLH