Hi all ...

In this thread [www.hallofmaat.com] we discussed many possibilities for The Sakkara Ostracon and although I was convinced it was based on a 1 by 1.3 rectangle it was shown by Jonny at Graham's that the best fit ellipse was actually semi-major axis 255.8612 and semi-minor axis of 178.0540. I was not happy with the result as I was sure it was 1:1.3 however math rules and so I grudgingly gave into the correctness of it.

From there I began to look for ratios in Egyptian architecture that would follow the basic outline of these measurements which works out to 1:1.436987 or 0.696 to 1

I then received an email from Andrew Conner, a Naval Architect and surveyor who had done a great deal of work on The Sakkara Ostracon in 2004. He brilliantly suggested as a solution a 3, 4 and 5 triangle with the hypotenuse of 5 swung around from one point on the triangle to the other to form an arch. His distances although not exact to The Sakkara Ostracon were close enough to make it look as if this could indeed be a very simple straight forward solution to designing the arch in question as the image below will show. Please be advised that all images are copyright to Andrew Conner and are published here with written permission.



His solution gave us as a radius 245 digits and a vertical height of the arch as 98 digits but his horizontal distance between points was not 1 cubit or 28 digits as was assumed in all previous solutions but turned out to be 39.2 digits or 1.4 cubits and instead of 5 cubits it worked out to 7 cubits or 7 x 28 or 196 digits.

I then simply turned it into a full circle as shown below:



And there it would have remained if not for the comment by Dave L that Andrew "knew" what this referred to and so I emailed Andrew Conner to see if he would let me in on what he had found ... and he did.

More later ....

Best
Don Barone

"There is nothing as impenetrable as a closed mind"
and ..." if everything is a coincidence what is the point of studying or measuring or analyzing anything ?" db