Hi Greg I had a great long post and I have just had yet another power cut (3rd in the last hour ( and it is gone so I will just go with a condensed version.

In regards to what you mentioned the site has this to say:

... Fig. 3 [www.egyptorigins.org] is a diagram embodying these assumptions; the vertical lines are proportional to the lengths stated on the ostrakon (all measurements are given in the convenient unit of the "finger"), and a curve has been drawn to touch the upper ends of these lines and to drop to the zero level on the right. It will be seen that the curve thus obtained gives a fairly good form, and is very similar to that of the ostrakon, except that it drops less sharply than does the latter between "41" and "0"; this difference however probably arises merely from the roughness of the drawing on the ostrakon. The curve does not appear to be part of an ellipse. ...

However I decided to analyze it and came up with this:



On the surface not too interesting until we take note of the fact like I have that 518 meters (length of enclosure + or - ) is equal to 989.12 cubits and that 989.12 divided into sq rt of 2 times 1000 = 1.43 and that 1034 / 723 is also equal to 1.43 reciprocal of 0.699

So we have this:



Is this the arch as pictured ? We need a better view of it.

Cheers
Don Barone



" If everything is simply a coincidence what then is the point of studying or measuring or analyzing anything in the ancient world ?" db