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May 8, 2024, 4:22 am UTC    
May 27, 2005 10:25AM
Here we go:

"The magnitude F of the centripetal force is equal to the mass m of the body times its velocity squared (v2) divided by the radius r of its path: F=mv2/r."

right - and for gravity - F=ma, where 'a' as Gravity is = 9.81m/s^2....

so F=mx9.81

so combining the two equations gives: mx9.81=mv2/r...cancel m's, 9.81=v2/r...

r=2000m, so 2000x9.81=19620....so V2 = 19620, so v=140m/s...or about 500kmph...

Haven't done that for years so it may be wrong..

Dave L

Subject Author Posted

Physics question

Pete Clarke May 27, 2005 09:54AM

Re: Physics question

Mercury Rapids May 27, 2005 09:55AM

Re: Physics question

Dave L May 27, 2005 10:25AM

Re: Physics question

Stephen Tonkin May 27, 2005 03:31PM

Re: Physics question

wirelessguru1 May 27, 2005 04:33PM

Re: Physics question

laura May 27, 2005 04:36PM

Re: Physics question

wirelessguru1 May 27, 2005 04:58PM

Re: Physics question

laura May 28, 2005 02:50AM

Re: Physics question

lobo-hotei May 27, 2005 06:46PM

Re: Physics question

Stephen Tonkin May 27, 2005 03:28PM

Re: Physics question

Pete Clarke June 01, 2005 02:54AM



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